Masukkan persamaan atau masalah
Input kamera tidak dikenali!

Penyelesaian - Absolute value equations

Exact form: z=-12
z=-\frac{1}{2}
Decimal form: z=0.5
z=-0.5

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|z+2|=|z1|
without the absolute value bars:

|x|=|y||z+2|=|z1|
x=+y(z+2)=(z1)
x=y(z+2)=(z1)
+x=y(z+2)=(z1)
x=y(z+2)=(z1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||z+2|=|z1|
x=+y , +x=y(z+2)=(z1)
x=y , x=y(z+2)=(z1)

2. Solve the two equations for z

5 additional steps

(z+2)=(z-1)

Subtract from both sides:

(z+2)-z=(z-1)-z

Kumpulkan sebutan sejenis:

(z-z)+2=(z-1)-z

Permudahkan aritmetik:

2=(z-1)-z

Kumpulkan sebutan sejenis:

2=(z-z)-1

Permudahkan aritmetik:

2=1

Pernyataan ini palsu:

2=1

The equation is false so it has no solution.

10 additional steps

(z+2)=-(z-1)

Expand the parentheses:

(z+2)=-z+1

Add to both sides:

(z+2)+z=(-z+1)+z

Kumpulkan sebutan sejenis:

(z+z)+2=(-z+1)+z

Permudahkan aritmetik:

2z+2=(-z+1)+z

Kumpulkan sebutan sejenis:

2z+2=(-z+z)+1

Permudahkan aritmetik:

2z+2=1

Subtract from both sides:

(2z+2)-2=1-2

Permudahkan aritmetik:

2z=12

Permudahkan aritmetik:

2z=1

Divide both sides by :

(2z)2=-12

Permudahkan pecahan:

z=-12

3. Graph

Each line represents the function of one side of the equation:
y=|z+2|
y=|z1|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.