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Penyelesaian - Absolute value equations

Exact form: x=4
x=4

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x5|=|x3|
without the absolute value bars:

|x|=|y||x5|=|x3|
x=+y(x5)=(x3)
x=y(x5)=(x3)
+x=y(x5)=(x3)
x=y(x5)=(x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x5|=|x3|
x=+y , +x=y(x5)=(x3)
x=y , x=y(x5)=(x3)

2. Solve the two equations for x

5 additional steps

(x-5)=(x-3)

Subtract from both sides:

(x-5)-x=(x-3)-x

Kumpulkan sebutan sejenis:

(x-x)-5=(x-3)-x

Permudahkan aritmetik:

-5=(x-3)-x

Kumpulkan sebutan sejenis:

-5=(x-x)-3

Permudahkan aritmetik:

5=3

Pernyataan ini palsu:

5=3

The equation is false so it has no solution.

12 additional steps

(x-5)=-(x-3)

Expand the parentheses:

(x-5)=-x+3

Add to both sides:

(x-5)+x=(-x+3)+x

Kumpulkan sebutan sejenis:

(x+x)-5=(-x+3)+x

Permudahkan aritmetik:

2x-5=(-x+3)+x

Kumpulkan sebutan sejenis:

2x-5=(-x+x)+3

Permudahkan aritmetik:

2x5=3

Add to both sides:

(2x-5)+5=3+5

Permudahkan aritmetik:

2x=3+5

Permudahkan aritmetik:

2x=8

Divide both sides by :

(2x)2=82

Permudahkan pecahan:

x=82

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(4·2)(1·2)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=4

3. Graph

Each line represents the function of one side of the equation:
y=|x5|
y=|x3|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.