Masukkan persamaan atau masalah
Input kamera tidak dikenali!

Penyelesaian - Absolute value equations

Exact form: x=-6,43
x=-6 , \frac{4}{3}
Mixed number form: x=-6,113
x=-6 , 1\frac{1}{3}
Decimal form: x=6,1.333
x=-6 , 1.333

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x5|=|2x+1|
without the absolute value bars:

|x|=|y||x5|=|2x+1|
x=+y(x5)=(2x+1)
x=y(x5)=(2x+1)
+x=y(x5)=(2x+1)
x=y(x5)=(2x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x5|=|2x+1|
x=+y , +x=y(x5)=(2x+1)
x=y , x=y(x5)=(2x+1)

2. Solve the two equations for x

10 additional steps

(x-5)=(2x+1)

Subtract from both sides:

(x-5)-2x=(2x+1)-2x

Kumpulkan sebutan sejenis:

(x-2x)-5=(2x+1)-2x

Permudahkan aritmetik:

-x-5=(2x+1)-2x

Kumpulkan sebutan sejenis:

-x-5=(2x-2x)+1

Permudahkan aritmetik:

x5=1

Add to both sides:

(-x-5)+5=1+5

Permudahkan aritmetik:

x=1+5

Permudahkan aritmetik:

x=6

Multiply both sides by :

-x·-1=6·-1

Buang nilai satu:

x=6·-1

Permudahkan aritmetik:

x=6

10 additional steps

(x-5)=-(2x+1)

Expand the parentheses:

(x-5)=-2x-1

Add to both sides:

(x-5)+2x=(-2x-1)+2x

Kumpulkan sebutan sejenis:

(x+2x)-5=(-2x-1)+2x

Permudahkan aritmetik:

3x-5=(-2x-1)+2x

Kumpulkan sebutan sejenis:

3x-5=(-2x+2x)-1

Permudahkan aritmetik:

3x5=1

Add to both sides:

(3x-5)+5=-1+5

Permudahkan aritmetik:

3x=1+5

Permudahkan aritmetik:

3x=4

Divide both sides by :

(3x)3=43

Permudahkan pecahan:

x=43

3. List the solutions

x=-6,43
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x5|
y=|2x+1|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.