Masukkan persamaan atau masalah
Input kamera tidak dikenali!

Penyelesaian - Absolute value equations

Exact form: x=0,-43
x=0 , -\frac{4}{3}
Mixed number form: x=0,-113
x=0 , -1\frac{1}{3}
Decimal form: x=0,1.333
x=0 , -1.333

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+2|=2|x+1|
without the absolute value bars:

|x|=|y||x+2|=2|x+1|
x=+y(x+2)=2(x+1)
x=y(x+2)=2((x+1))
+x=y(x+2)=2(x+1)
x=y(x+2)=2(x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+2|=2|x+1|
x=+y , +x=y(x+2)=2(x+1)
x=y , x=y(x+2)=2((x+1))

2. Solve the two equations for x

12 additional steps

(x+2)=2·(x+1)

Expand the parentheses:

(x+2)=2x+2·1

Permudahkan aritmetik:

(x+2)=2x+2

Subtract from both sides:

(x+2)-2x=(2x+2)-2x

Kumpulkan sebutan sejenis:

(x-2x)+2=(2x+2)-2x

Permudahkan aritmetik:

-x+2=(2x+2)-2x

Kumpulkan sebutan sejenis:

-x+2=(2x-2x)+2

Permudahkan aritmetik:

x+2=2

Subtract from both sides:

(-x+2)-2=2-2

Permudahkan aritmetik:

x=22

Permudahkan aritmetik:

x=0

Multiply both sides by :

-x·-1=0·-1

Buang nilai satu:

x=0·-1

Darab dengan sifar:

x=0

14 additional steps

(x+2)=2·(-(x+1))

Expand the parentheses:

(x+2)=2·(-x-1)

(x+2)=2·-x+2·-1

Kumpulkan sebutan sejenis:

(x+2)=(2·-1)x+2·-1

Darabkan pekali:

(x+2)=-2x+2·-1

Permudahkan aritmetik:

(x+2)=-2x-2

Add to both sides:

(x+2)+2x=(-2x-2)+2x

Kumpulkan sebutan sejenis:

(x+2x)+2=(-2x-2)+2x

Permudahkan aritmetik:

3x+2=(-2x-2)+2x

Kumpulkan sebutan sejenis:

3x+2=(-2x+2x)-2

Permudahkan aritmetik:

3x+2=2

Subtract from both sides:

(3x+2)-2=-2-2

Permudahkan aritmetik:

3x=22

Permudahkan aritmetik:

3x=4

Divide both sides by :

(3x)3=-43

Permudahkan pecahan:

x=-43

3. List the solutions

x=0,-43
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+2|
y=2|x+1|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.