Masukkan persamaan atau masalah
Input kamera tidak dikenali!

Penyelesaian - Absolute value equations

Exact form: x=12
x=\frac{1}{2}
Decimal form: x=0.5
x=0.5

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+2|=|x+3|
without the absolute value bars:

|x|=|y||x+2|=|x+3|
x=+y(x+2)=(x+3)
x=y(x+2)=(x+3)
+x=y(x+2)=(x+3)
x=y(x+2)=(x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+2|=|x+3|
x=+y , +x=y(x+2)=(x+3)
x=y , x=y(x+2)=(x+3)

2. Solve the two equations for x

9 additional steps

(x+2)=(-x+3)

Add to both sides:

(x+2)+x=(-x+3)+x

Kumpulkan sebutan sejenis:

(x+x)+2=(-x+3)+x

Permudahkan aritmetik:

2x+2=(-x+3)+x

Kumpulkan sebutan sejenis:

2x+2=(-x+x)+3

Permudahkan aritmetik:

2x+2=3

Subtract from both sides:

(2x+2)-2=3-2

Permudahkan aritmetik:

2x=32

Permudahkan aritmetik:

2x=1

Divide both sides by :

(2x)2=12

Permudahkan pecahan:

x=12

6 additional steps

(x+2)=-(-x+3)

Expand the parentheses:

(x+2)=x-3

Subtract from both sides:

(x+2)-x=(x-3)-x

Kumpulkan sebutan sejenis:

(x-x)+2=(x-3)-x

Permudahkan aritmetik:

2=(x-3)-x

Kumpulkan sebutan sejenis:

2=(x-x)-3

Permudahkan aritmetik:

2=3

Pernyataan ini palsu:

2=3

The equation is false so it has no solution.

3. List the solutions

x=12
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+2|
y=|x+3|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.