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Penyelesaian - Absolute value equations

Exact form: x=-35,-13
x=-\frac{3}{5} , -\frac{1}{3}
Decimal form: x=0.6,0.333
x=-0.6 , -0.333

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+1|=|4x2|
without the absolute value bars:

|x|=|y||x+1|=|4x2|
x=+y(x+1)=(4x2)
x=y(x+1)=(4x2)
+x=y(x+1)=(4x2)
x=y(x+1)=(4x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+1|=|4x2|
x=+y , +x=y(x+1)=(4x2)
x=y , x=y(x+1)=(4x2)

2. Solve the two equations for x

9 additional steps

(x+1)=(-4x-2)

Add to both sides:

(x+1)+4x=(-4x-2)+4x

Kumpulkan sebutan sejenis:

(x+4x)+1=(-4x-2)+4x

Permudahkan aritmetik:

5x+1=(-4x-2)+4x

Kumpulkan sebutan sejenis:

5x+1=(-4x+4x)-2

Permudahkan aritmetik:

5x+1=2

Subtract from both sides:

(5x+1)-1=-2-1

Permudahkan aritmetik:

5x=21

Permudahkan aritmetik:

5x=3

Divide both sides by :

(5x)5=-35

Permudahkan pecahan:

x=-35

12 additional steps

(x+1)=-(-4x-2)

Expand the parentheses:

(x+1)=4x+2

Subtract from both sides:

(x+1)-4x=(4x+2)-4x

Kumpulkan sebutan sejenis:

(x-4x)+1=(4x+2)-4x

Permudahkan aritmetik:

-3x+1=(4x+2)-4x

Kumpulkan sebutan sejenis:

-3x+1=(4x-4x)+2

Permudahkan aritmetik:

3x+1=2

Subtract from both sides:

(-3x+1)-1=2-1

Permudahkan aritmetik:

3x=21

Permudahkan aritmetik:

3x=1

Divide both sides by :

(-3x)-3=1-3

Hapuskan tanda negatif:

3x3=1-3

Permudahkan pecahan:

x=1-3

Pindahkan tanda negatif dari penyebut ke pembilang:

x=-13

3. List the solutions

x=-35,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+1|
y=|4x2|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.