Masukkan persamaan atau masalah
Input kamera tidak dikenali!

Penyelesaian - Absolute value equations

Exact form: u=-13,-73
u=-13 , -\frac{7}{3}
Mixed number form: u=-13,-213
u=-13 , -2\frac{1}{3}
Decimal form: u=13,2.333
u=-13 , -2.333

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|u3|=|2u+10|
without the absolute value bars:

|x|=|y||u3|=|2u+10|
x=+y(u3)=(2u+10)
x=y(u3)=(2u+10)
+x=y(u3)=(2u+10)
x=y(u3)=(2u+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||u3|=|2u+10|
x=+y , +x=y(u3)=(2u+10)
x=y , x=y(u3)=(2u+10)

2. Solve the two equations for u

10 additional steps

(u-3)=(2u+10)

Subtract from both sides:

(u-3)-2u=(2u+10)-2u

Kumpulkan sebutan sejenis:

(u-2u)-3=(2u+10)-2u

Permudahkan aritmetik:

-u-3=(2u+10)-2u

Kumpulkan sebutan sejenis:

-u-3=(2u-2u)+10

Permudahkan aritmetik:

u3=10

Add to both sides:

(-u-3)+3=10+3

Permudahkan aritmetik:

u=10+3

Permudahkan aritmetik:

u=13

Multiply both sides by :

-u·-1=13·-1

Buang nilai satu:

u=13·-1

Permudahkan aritmetik:

u=13

10 additional steps

(u-3)=-(2u+10)

Expand the parentheses:

(u-3)=-2u-10

Add to both sides:

(u-3)+2u=(-2u-10)+2u

Kumpulkan sebutan sejenis:

(u+2u)-3=(-2u-10)+2u

Permudahkan aritmetik:

3u-3=(-2u-10)+2u

Kumpulkan sebutan sejenis:

3u-3=(-2u+2u)-10

Permudahkan aritmetik:

3u3=10

Add to both sides:

(3u-3)+3=-10+3

Permudahkan aritmetik:

3u=10+3

Permudahkan aritmetik:

3u=7

Divide both sides by :

(3u)3=-73

Permudahkan pecahan:

u=-73

3. List the solutions

u=-13,-73
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|u3|
y=|2u+10|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.