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Penyelesaian - Absolute value equations

Exact form: x=-1,35
x=-1 , \frac{3}{5}
Decimal form: x=1,0.6
x=-1 , 0.6

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x5|=|8x4|
without the absolute value bars:

|x|=|y||7x5|=|8x4|
x=+y(7x5)=(8x4)
x=y(7x5)=(8x4)
+x=y(7x5)=(8x4)
x=y(7x5)=(8x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x5|=|8x4|
x=+y , +x=y(7x5)=(8x4)
x=y , x=y(7x5)=(8x4)

2. Solve the two equations for x

10 additional steps

(7x-5)=(8x-4)

Subtract from both sides:

(7x-5)-8x=(8x-4)-8x

Kumpulkan sebutan sejenis:

(7x-8x)-5=(8x-4)-8x

Permudahkan aritmetik:

-x-5=(8x-4)-8x

Kumpulkan sebutan sejenis:

-x-5=(8x-8x)-4

Permudahkan aritmetik:

x5=4

Add to both sides:

(-x-5)+5=-4+5

Permudahkan aritmetik:

x=4+5

Permudahkan aritmetik:

x=1

Multiply both sides by :

-x·-1=1·-1

Buang nilai satu:

x=1·-1

Buang nilai satu:

x=1

12 additional steps

(7x-5)=-(8x-4)

Expand the parentheses:

(7x-5)=-8x+4

Add to both sides:

(7x-5)+8x=(-8x+4)+8x

Kumpulkan sebutan sejenis:

(7x+8x)-5=(-8x+4)+8x

Permudahkan aritmetik:

15x-5=(-8x+4)+8x

Kumpulkan sebutan sejenis:

15x-5=(-8x+8x)+4

Permudahkan aritmetik:

15x5=4

Add to both sides:

(15x-5)+5=4+5

Permudahkan aritmetik:

15x=4+5

Permudahkan aritmetik:

15x=9

Divide both sides by :

(15x)15=915

Permudahkan pecahan:

x=915

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(3·3)(5·3)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=35

3. List the solutions

x=-1,35
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x5|
y=|8x4|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.