Masukkan persamaan atau masalah
Input kamera tidak dikenali!

Penyelesaian - Absolute value equations

Exact form: y=-1,15
y=-1 , \frac{1}{5}
Decimal form: y=1,0.2
y=-1 , 0.2

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6y|=2|2y1|
without the absolute value bars:

|x|=|y||6y|=2|2y1|
x=+y(6y)=2(2y1)
x=y(6y)=2((2y1))
+x=y(6y)=2(2y1)
x=y(6y)=2(2y1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6y|=2|2y1|
x=+y , +x=y(6y)=2(2y1)
x=y , x=y(6y)=2((2y1))

2. Solve the two equations for y

9 additional steps

6y=2·(2y-1)

Kembangkan tanda kurung:

6y=2·2y+2·-1

Darabkan pekali:

6y=4y+2·-1

Permudahkan aritmetik:

6y=4y2

Subtract from both sides:

(6y)-4y=(4y-2)-4y

Permudahkan aritmetik:

2y=(4y-2)-4y

Kumpulkan sebutan sejenis:

2y=(4y-4y)-2

Permudahkan aritmetik:

2y=2

Divide both sides by :

(2y)2=-22

Permudahkan pecahan:

y=-22

Permudahkan pecahan:

y=1

11 additional steps

6y=2·(-(2y-1))

Expand the parentheses:

6y=2·(-2y+1)

Kembangkan tanda kurung:

6y=2·-2y+2·1

Darabkan pekali:

6y=-4y+2·1

Permudahkan aritmetik:

6y=4y+2

Add to both sides:

(6y)+4y=(-4y+2)+4y

Permudahkan aritmetik:

10y=(-4y+2)+4y

Kumpulkan sebutan sejenis:

10y=(-4y+4y)+2

Permudahkan aritmetik:

10y=2

Divide both sides by :

(10y)10=210

Permudahkan pecahan:

y=210

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

y=(1·2)(5·2)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

y=15

3. List the solutions

y=-1,15
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6y|
y=2|2y1|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.