Masukkan persamaan atau masalah
Input kamera tidak dikenali!

Penyelesaian - Absolute value equations

Exact form: x=23,27
x=\frac{2}{3} , \frac{2}{7}
Decimal form: x=0.667,0.286
x=0.667 , 0.286

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x2|=|2x|
without the absolute value bars:

|x|=|y||5x2|=|2x|
x=+y(5x2)=(2x)
x=y(5x2)=(2x)
+x=y(5x2)=(2x)
x=y(5x2)=(2x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x2|=|2x|
x=+y , +x=y(5x2)=(2x)
x=y , x=y(5x2)=(2x)

2. Solve the two equations for x

8 additional steps

(5x-2)=2x

Subtract from both sides:

(5x-2)-2x=(2x)-2x

Kumpulkan sebutan sejenis:

(5x-2x)-2=(2x)-2x

Permudahkan aritmetik:

3x-2=(2x)-2x

Permudahkan aritmetik:

3x2=0

Add to both sides:

(3x-2)+2=0+2

Permudahkan aritmetik:

3x=0+2

Permudahkan aritmetik:

3x=2

Divide both sides by :

(3x)3=23

Permudahkan pecahan:

x=23

7 additional steps

(5x-2)=-2x

Add to both sides:

(5x-2)+2=(-2x)+2

Permudahkan aritmetik:

5x=(-2x)+2

Add to both sides:

(5x)+2x=((-2x)+2)+2x

Permudahkan aritmetik:

7x=((-2x)+2)+2x

Kumpulkan sebutan sejenis:

7x=(-2x+2x)+2

Permudahkan aritmetik:

7x=2

Divide both sides by :

(7x)7=27

Permudahkan pecahan:

x=27

3. List the solutions

x=23,27
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x2|
y=|2x|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.