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Penyelesaian - Absolute value equations

Exact form: u=-32
u=-\frac{3}{2}
Mixed number form: u=-112
u=-1\frac{1}{2}
Decimal form: u=1.5
u=-1.5

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5u+8|=|5u+7|
without the absolute value bars:

|x|=|y||5u+8|=|5u+7|
x=+y(5u+8)=(5u+7)
x=y(5u+8)=(5u+7)
+x=y(5u+8)=(5u+7)
x=y(5u+8)=(5u+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5u+8|=|5u+7|
x=+y , +x=y(5u+8)=(5u+7)
x=y , x=y(5u+8)=(5u+7)

2. Solve the two equations for u

5 additional steps

(5u+8)=(5u+7)

Subtract from both sides:

(5u+8)-5u=(5u+7)-5u

Kumpulkan sebutan sejenis:

(5u-5u)+8=(5u+7)-5u

Permudahkan aritmetik:

8=(5u+7)-5u

Kumpulkan sebutan sejenis:

8=(5u-5u)+7

Permudahkan aritmetik:

8=7

Pernyataan ini palsu:

8=7

The equation is false so it has no solution.

12 additional steps

(5u+8)=-(5u+7)

Expand the parentheses:

(5u+8)=-5u-7

Add to both sides:

(5u+8)+5u=(-5u-7)+5u

Kumpulkan sebutan sejenis:

(5u+5u)+8=(-5u-7)+5u

Permudahkan aritmetik:

10u+8=(-5u-7)+5u

Kumpulkan sebutan sejenis:

10u+8=(-5u+5u)-7

Permudahkan aritmetik:

10u+8=7

Subtract from both sides:

(10u+8)-8=-7-8

Permudahkan aritmetik:

10u=78

Permudahkan aritmetik:

10u=15

Divide both sides by :

(10u)10=-1510

Permudahkan pecahan:

u=-1510

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

u=(-3·5)(2·5)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

u=-32

3. Graph

Each line represents the function of one side of the equation:
y=|5u+8|
y=|5u+7|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.