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Penyelesaian - Absolute value equations

Exact form: x=1,17
x=1 , \frac{1}{7}
Decimal form: x=1,0.143
x=1 , 0.143

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x+5|=|x4|
without the absolute value bars:

|x|=|y||8x+5|=|x4|
x=+y(8x+5)=(x4)
x=y(8x+5)=(x4)
+x=y(8x+5)=(x4)
x=y(8x+5)=(x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x+5|=|x4|
x=+y , +x=y(8x+5)=(x4)
x=y , x=y(8x+5)=(x4)

2. Solve the two equations for x

12 additional steps

(-8x+5)=(x-4)

Subtract from both sides:

(-8x+5)-x=(x-4)-x

Kumpulkan sebutan sejenis:

(-8x-x)+5=(x-4)-x

Permudahkan aritmetik:

-9x+5=(x-4)-x

Kumpulkan sebutan sejenis:

-9x+5=(x-x)-4

Permudahkan aritmetik:

9x+5=4

Subtract from both sides:

(-9x+5)-5=-4-5

Permudahkan aritmetik:

9x=45

Permudahkan aritmetik:

9x=9

Divide both sides by :

(-9x)-9=-9-9

Hapuskan tanda negatif:

9x9=-9-9

Permudahkan pecahan:

x=-9-9

Hapuskan tanda negatif:

x=99

Permudahkan pecahan:

x=1

12 additional steps

(-8x+5)=-(x-4)

Expand the parentheses:

(-8x+5)=-x+4

Add to both sides:

(-8x+5)+x=(-x+4)+x

Kumpulkan sebutan sejenis:

(-8x+x)+5=(-x+4)+x

Permudahkan aritmetik:

-7x+5=(-x+4)+x

Kumpulkan sebutan sejenis:

-7x+5=(-x+x)+4

Permudahkan aritmetik:

7x+5=4

Subtract from both sides:

(-7x+5)-5=4-5

Permudahkan aritmetik:

7x=45

Permudahkan aritmetik:

7x=1

Divide both sides by :

(-7x)-7=-1-7

Hapuskan tanda negatif:

7x7=-1-7

Permudahkan pecahan:

x=-1-7

Hapuskan tanda negatif:

x=17

3. List the solutions

x=1,17
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x+5|
y=|x4|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.