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Penyelesaian - Absolute value equations

Exact form: x=-112,-18
x=-\frac{11}{2} , -\frac{1}{8}
Mixed number form: x=-512,-18
x=-5\frac{1}{2} , -\frac{1}{8}
Decimal form: x=5.5,0.125
x=-5.5 , -0.125

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x5|=|5x+6|
without the absolute value bars:

|x|=|y||3x5|=|5x+6|
x=+y(3x5)=(5x+6)
x=y(3x5)=(5x+6)
+x=y(3x5)=(5x+6)
x=y(3x5)=(5x+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x5|=|5x+6|
x=+y , +x=y(3x5)=(5x+6)
x=y , x=y(3x5)=(5x+6)

2. Solve the two equations for x

11 additional steps

(3x-5)=(5x+6)

Subtract from both sides:

(3x-5)-5x=(5x+6)-5x

Kumpulkan sebutan sejenis:

(3x-5x)-5=(5x+6)-5x

Permudahkan aritmetik:

-2x-5=(5x+6)-5x

Kumpulkan sebutan sejenis:

-2x-5=(5x-5x)+6

Permudahkan aritmetik:

2x5=6

Add to both sides:

(-2x-5)+5=6+5

Permudahkan aritmetik:

2x=6+5

Permudahkan aritmetik:

2x=11

Divide both sides by :

(-2x)-2=11-2

Hapuskan tanda negatif:

2x2=11-2

Permudahkan pecahan:

x=11-2

Pindahkan tanda negatif dari penyebut ke pembilang:

x=-112

10 additional steps

(3x-5)=-(5x+6)

Expand the parentheses:

(3x-5)=-5x-6

Add to both sides:

(3x-5)+5x=(-5x-6)+5x

Kumpulkan sebutan sejenis:

(3x+5x)-5=(-5x-6)+5x

Permudahkan aritmetik:

8x-5=(-5x-6)+5x

Kumpulkan sebutan sejenis:

8x-5=(-5x+5x)-6

Permudahkan aritmetik:

8x5=6

Add to both sides:

(8x-5)+5=-6+5

Permudahkan aritmetik:

8x=6+5

Permudahkan aritmetik:

8x=1

Divide both sides by :

(8x)8=-18

Permudahkan pecahan:

x=-18

3. List the solutions

x=-112,-18
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x5|
y=|5x+6|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.