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Penyelesaian - Absolute value equations

Exact form: x=-2,12
x=-2 , \frac{1}{2}
Decimal form: x=2,0.5
x=-2 , 0.5

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+1|=|x3|
without the absolute value bars:

|x|=|y||3x+1|=|x3|
x=+y(3x+1)=(x3)
x=y(3x+1)=(x3)
+x=y(3x+1)=(x3)
x=y(3x+1)=(x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+1|=|x3|
x=+y , +x=y(3x+1)=(x3)
x=y , x=y(3x+1)=(x3)

2. Solve the two equations for x

11 additional steps

(3x+1)=(x-3)

Subtract from both sides:

(3x+1)-x=(x-3)-x

Kumpulkan sebutan sejenis:

(3x-x)+1=(x-3)-x

Permudahkan aritmetik:

2x+1=(x-3)-x

Kumpulkan sebutan sejenis:

2x+1=(x-x)-3

Permudahkan aritmetik:

2x+1=3

Subtract from both sides:

(2x+1)-1=-3-1

Permudahkan aritmetik:

2x=31

Permudahkan aritmetik:

2x=4

Divide both sides by :

(2x)2=-42

Permudahkan pecahan:

x=-42

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(-2·2)(1·2)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=2

12 additional steps

(3x+1)=-(x-3)

Expand the parentheses:

(3x+1)=-x+3

Add to both sides:

(3x+1)+x=(-x+3)+x

Kumpulkan sebutan sejenis:

(3x+x)+1=(-x+3)+x

Permudahkan aritmetik:

4x+1=(-x+3)+x

Kumpulkan sebutan sejenis:

4x+1=(-x+x)+3

Permudahkan aritmetik:

4x+1=3

Subtract from both sides:

(4x+1)-1=3-1

Permudahkan aritmetik:

4x=31

Permudahkan aritmetik:

4x=2

Divide both sides by :

(4x)4=24

Permudahkan pecahan:

x=24

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(1·2)(2·2)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=12

3. List the solutions

x=-2,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+1|
y=|x3|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.