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Penyelesaian - Absolute value equations

Exact form: a=6,-47
a=6 , -\frac{4}{7}
Decimal form: a=6,0.571
a=6 , -0.571

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3a+5|=|4a1|
without the absolute value bars:

|x|=|y||3a+5|=|4a1|
x=+y(3a+5)=(4a1)
x=y(3a+5)=(4a1)
+x=y(3a+5)=(4a1)
x=y(3a+5)=(4a1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3a+5|=|4a1|
x=+y , +x=y(3a+5)=(4a1)
x=y , x=y(3a+5)=(4a1)

2. Solve the two equations for a

10 additional steps

(3a+5)=(4a-1)

Subtract from both sides:

(3a+5)-4a=(4a-1)-4a

Kumpulkan sebutan sejenis:

(3a-4a)+5=(4a-1)-4a

Permudahkan aritmetik:

-a+5=(4a-1)-4a

Kumpulkan sebutan sejenis:

-a+5=(4a-4a)-1

Permudahkan aritmetik:

a+5=1

Subtract from both sides:

(-a+5)-5=-1-5

Permudahkan aritmetik:

a=15

Permudahkan aritmetik:

a=6

Multiply both sides by :

-a·-1=-6·-1

Buang nilai satu:

a=-6·-1

Permudahkan aritmetik:

a=6

10 additional steps

(3a+5)=-(4a-1)

Expand the parentheses:

(3a+5)=-4a+1

Add to both sides:

(3a+5)+4a=(-4a+1)+4a

Kumpulkan sebutan sejenis:

(3a+4a)+5=(-4a+1)+4a

Permudahkan aritmetik:

7a+5=(-4a+1)+4a

Kumpulkan sebutan sejenis:

7a+5=(-4a+4a)+1

Permudahkan aritmetik:

7a+5=1

Subtract from both sides:

(7a+5)-5=1-5

Permudahkan aritmetik:

7a=15

Permudahkan aritmetik:

7a=4

Divide both sides by :

(7a)7=-47

Permudahkan pecahan:

a=-47

3. List the solutions

a=6,-47
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3a+5|
y=|4a1|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.