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Penyelesaian - Absolute value equations

Exact form: y=13,1
y=-13 , -1

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2y+5|=12|3y-3|
without the absolute value bars:

|x|=|y||2y+5|=12|3y-3|
x=+y(2y+5)=12(3y-3)
x=-y(2y+5)=12(-(3y-3))
+x=y(2y+5)=12(3y-3)
-x=y-(2y+5)=12(3y-3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2y+5|=12|3y-3|
x=+y , +x=y(2y+5)=12(3y-3)
x=-y , -x=y(2y+5)=12(-(3y-3))

2. Solve the two equations for y

23 additional steps

(2y+5)=12·(3y-3)

Darabkan pecahan:

(2y+5)=(1·(3y-3))2

Pecahkan pecahan:

(2y+5)=3y2+-32

Subtract from both sides:

(2y+5)-3y2=(3y2+-32)-3y2

Kumpulkan sebutan sejenis:

(2y+-32y)+5=(3y2+-32)-3y2

Kumpulkan pekali:

(2+-32)y+5=(3y2+-32)-3y2

Tukar nombor bulat kepada pecahan:

(42+-32)y+5=(3y2+-32)-3y2

Gabungkan pecahan:

(4-3)2y+5=(3y2+-32)-3y2

Gabungkan pembilang:

12y+5=(3y2+-32)-3y2

Kumpulkan sebutan sejenis:

12·y+5=(3y2+-32y)+-32

Gabungkan pecahan:

12·y+5=(3-3)2y+-32

Gabungkan pembilang:

12·y+5=02y+-32

Permudahkan pembilang sifar:

12y+5=0y+-32

Permudahkan aritmetik:

12y+5=-32

Subtract from both sides:

(12y+5)-5=(-32)-5

Permudahkan aritmetik:

12y=(-32)-5

Tukar nombor bulat kepada pecahan:

12y=-32+-102

Gabungkan pecahan:

12y=(-3-10)2

Gabungkan pembilang:

12y=-132

Multiply both sides by inverse fraction :

(12y)·21=(-132)·21

Kumpulkan sebutan sejenis:

(12·2)y=(-132)·21

Darabkan pekali:

(1·2)2y=(-132)·21

Permudahkan pecahan:

y=(-132)·21

Darabkan pecahan:

y=(-13·2)2

Permudahkan aritmetik:

y=13

24 additional steps

(2y+5)=12·(-(3y-3))

Darabkan pecahan:

(2y+5)=(1·(-(3y-3)))2

Expand the parentheses:

(2y+5)=(-3y+3)2

Pecahkan pecahan:

(2y+5)=-3y2+32

Add to both sides:

(2y+5)+32·y=(-3y2+32)+32y

Kumpulkan sebutan sejenis:

(2y+32·y)+5=(-3y2+32)+32y

Kumpulkan pekali:

(2+32)y+5=(-3y2+32)+32y

Tukar nombor bulat kepada pecahan:

(42+32)y+5=(-3y2+32)+32y

Gabungkan pecahan:

(4+3)2·y+5=(-3y2+32)+32y

Gabungkan pembilang:

72·y+5=(-3y2+32)+32y

Kumpulkan sebutan sejenis:

72·y+5=(-3y2+32y)+32

Gabungkan pecahan:

72·y+5=(-3+3)2y+32

Gabungkan pembilang:

72·y+5=02y+32

Permudahkan pembilang sifar:

72y+5=0y+32

Permudahkan aritmetik:

72y+5=32

Subtract from both sides:

(72y+5)-5=(32)-5

Permudahkan aritmetik:

72y=(32)-5

Tukar nombor bulat kepada pecahan:

72y=32+-102

Gabungkan pecahan:

72y=(3-10)2

Gabungkan pembilang:

72y=-72

Multiply both sides by inverse fraction :

(72y)·27=(-72)·27

Kumpulkan sebutan sejenis:

(72·27)y=(-72)·27

Darabkan pekali:

(7·2)(2·7)y=(-72)·27

Permudahkan pecahan:

y=(-72)·27

Darabkan pecahan:

y=(-7·2)(2·7)

Permudahkan aritmetik:

y=1

3. List the solutions

y=13,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2y+5|
y=12|3y-3|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.