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Penyelesaian - Absolute value equations

Exact form: x=2,114
x=2 , \frac{11}{4}
Mixed number form: x=2,234
x=2 , 2\frac{3}{4}
Decimal form: x=2,2.75
x=2 , 2.75

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x7|=|6x15|
without the absolute value bars:

|x|=|y||2x7|=|6x15|
x=+y(2x7)=(6x15)
x=y(2x7)=(6x15)
+x=y(2x7)=(6x15)
x=y(2x7)=(6x15)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x7|=|6x15|
x=+y , +x=y(2x7)=(6x15)
x=y , x=y(2x7)=(6x15)

2. Solve the two equations for x

13 additional steps

(2x-7)=(6x-15)

Subtract from both sides:

(2x-7)-6x=(6x-15)-6x

Kumpulkan sebutan sejenis:

(2x-6x)-7=(6x-15)-6x

Permudahkan aritmetik:

-4x-7=(6x-15)-6x

Kumpulkan sebutan sejenis:

-4x-7=(6x-6x)-15

Permudahkan aritmetik:

4x7=15

Add to both sides:

(-4x-7)+7=-15+7

Permudahkan aritmetik:

4x=15+7

Permudahkan aritmetik:

4x=8

Divide both sides by :

(-4x)-4=-8-4

Hapuskan tanda negatif:

4x4=-8-4

Permudahkan pecahan:

x=-8-4

Hapuskan tanda negatif:

x=84

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(2·4)(1·4)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=2

12 additional steps

(2x-7)=-(6x-15)

Expand the parentheses:

(2x-7)=-6x+15

Add to both sides:

(2x-7)+6x=(-6x+15)+6x

Kumpulkan sebutan sejenis:

(2x+6x)-7=(-6x+15)+6x

Permudahkan aritmetik:

8x-7=(-6x+15)+6x

Kumpulkan sebutan sejenis:

8x-7=(-6x+6x)+15

Permudahkan aritmetik:

8x7=15

Add to both sides:

(8x-7)+7=15+7

Permudahkan aritmetik:

8x=15+7

Permudahkan aritmetik:

8x=22

Divide both sides by :

(8x)8=228

Permudahkan pecahan:

x=228

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(11·2)(4·2)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=114

3. List the solutions

x=2,114
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x7|
y=|6x15|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.