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Penyelesaian - Absolute value equations

Exact form: x=74
x=\frac{7}{4}
Mixed number form: x=134
x=1\frac{3}{4}
Decimal form: x=1.75
x=1.75

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=2|x+3|
without the absolute value bars:

|x|=|y||2x1|=2|x+3|
x=+y(2x1)=2(x+3)
x=y(2x1)=2((x+3))
+x=y(2x1)=2(x+3)
x=y(2x1)=2(x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=2|x+3|
x=+y , +x=y(2x1)=2(x+3)
x=y , x=y(2x1)=2((x+3))

2. Solve the two equations for x

13 additional steps

(2x-1)=2·(-x+3)

Expand the parentheses:

(2x-1)=2·-x+2·3

Kumpulkan sebutan sejenis:

(2x-1)=(2·-1)x+2·3

Darabkan pekali:

(2x-1)=-2x+2·3

Permudahkan aritmetik:

(2x-1)=-2x+6

Add to both sides:

(2x-1)+2x=(-2x+6)+2x

Kumpulkan sebutan sejenis:

(2x+2x)-1=(-2x+6)+2x

Permudahkan aritmetik:

4x-1=(-2x+6)+2x

Kumpulkan sebutan sejenis:

4x-1=(-2x+2x)+6

Permudahkan aritmetik:

4x1=6

Add to both sides:

(4x-1)+1=6+1

Permudahkan aritmetik:

4x=6+1

Permudahkan aritmetik:

4x=7

Divide both sides by :

(4x)4=74

Permudahkan pecahan:

x=74

8 additional steps

(2x-1)=2·(-(-x+3))

Expand the parentheses:

(2x-1)=2·(x-3)

(2x-1)=2x+2·-3

Permudahkan aritmetik:

(2x-1)=2x-6

Subtract from both sides:

(2x-1)-2x=(2x-6)-2x

Kumpulkan sebutan sejenis:

(2x-2x)-1=(2x-6)-2x

Permudahkan aritmetik:

-1=(2x-6)-2x

Kumpulkan sebutan sejenis:

-1=(2x-2x)-6

Permudahkan aritmetik:

1=6

Pernyataan ini palsu:

1=6

The equation is false so it has no solution.

3. List the solutions

x=74
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=2|x+3|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.