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Penyelesaian - Absolute value equations

Exact form: x=-2,-13
x=-2 , -\frac{1}{3}
Decimal form: x=2,0.333
x=-2 , -0.333

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=|4x+3|
without the absolute value bars:

|x|=|y||2x1|=|4x+3|
x=+y(2x1)=(4x+3)
x=y(2x1)=(4x+3)
+x=y(2x1)=(4x+3)
x=y(2x1)=(4x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=|4x+3|
x=+y , +x=y(2x1)=(4x+3)
x=y , x=y(2x1)=(4x+3)

2. Solve the two equations for x

13 additional steps

(2x-1)=(4x+3)

Subtract from both sides:

(2x-1)-4x=(4x+3)-4x

Kumpulkan sebutan sejenis:

(2x-4x)-1=(4x+3)-4x

Permudahkan aritmetik:

-2x-1=(4x+3)-4x

Kumpulkan sebutan sejenis:

-2x-1=(4x-4x)+3

Permudahkan aritmetik:

2x1=3

Add to both sides:

(-2x-1)+1=3+1

Permudahkan aritmetik:

2x=3+1

Permudahkan aritmetik:

2x=4

Divide both sides by :

(-2x)-2=4-2

Hapuskan tanda negatif:

2x2=4-2

Permudahkan pecahan:

x=4-2

Pindahkan tanda negatif dari penyebut ke pembilang:

x=-42

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(-2·2)(1·2)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=2

12 additional steps

(2x-1)=-(4x+3)

Expand the parentheses:

(2x-1)=-4x-3

Add to both sides:

(2x-1)+4x=(-4x-3)+4x

Kumpulkan sebutan sejenis:

(2x+4x)-1=(-4x-3)+4x

Permudahkan aritmetik:

6x-1=(-4x-3)+4x

Kumpulkan sebutan sejenis:

6x-1=(-4x+4x)-3

Permudahkan aritmetik:

6x1=3

Add to both sides:

(6x-1)+1=-3+1

Permudahkan aritmetik:

6x=3+1

Permudahkan aritmetik:

6x=2

Divide both sides by :

(6x)6=-26

Permudahkan pecahan:

x=-26

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(-1·2)(3·2)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=-13

3. List the solutions

x=-2,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=|4x+3|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.