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Penyelesaian - Absolute value equations

Exact form: x=-17,-1
x=-\frac{1}{7} , -1
Decimal form: x=0.143,1
x=-0.143 , -1

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=|5x2|
without the absolute value bars:

|x|=|y||2x1|=|5x2|
x=+y(2x1)=(5x2)
x=y(2x1)=(5x2)
+x=y(2x1)=(5x2)
x=y(2x1)=(5x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=|5x2|
x=+y , +x=y(2x1)=(5x2)
x=y , x=y(2x1)=(5x2)

2. Solve the two equations for x

9 additional steps

(2x-1)=(-5x-2)

Add to both sides:

(2x-1)+5x=(-5x-2)+5x

Kumpulkan sebutan sejenis:

(2x+5x)-1=(-5x-2)+5x

Permudahkan aritmetik:

7x-1=(-5x-2)+5x

Kumpulkan sebutan sejenis:

7x-1=(-5x+5x)-2

Permudahkan aritmetik:

7x1=2

Add to both sides:

(7x-1)+1=-2+1

Permudahkan aritmetik:

7x=2+1

Permudahkan aritmetik:

7x=1

Divide both sides by :

(7x)7=-17

Permudahkan pecahan:

x=-17

13 additional steps

(2x-1)=-(-5x-2)

Expand the parentheses:

(2x-1)=5x+2

Subtract from both sides:

(2x-1)-5x=(5x+2)-5x

Kumpulkan sebutan sejenis:

(2x-5x)-1=(5x+2)-5x

Permudahkan aritmetik:

-3x-1=(5x+2)-5x

Kumpulkan sebutan sejenis:

-3x-1=(5x-5x)+2

Permudahkan aritmetik:

3x1=2

Add to both sides:

(-3x-1)+1=2+1

Permudahkan aritmetik:

3x=2+1

Permudahkan aritmetik:

3x=3

Divide both sides by :

(-3x)-3=3-3

Hapuskan tanda negatif:

3x3=3-3

Permudahkan pecahan:

x=3-3

Pindahkan tanda negatif dari penyebut ke pembilang:

x=-33

Permudahkan pecahan:

x=1

3. List the solutions

x=-17,-1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=|5x2|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.