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Penyelesaian - Absolute value equations

Exact form: x=15,15
x=15 , \frac{1}{5}
Decimal form: x=15,0.2
x=15 , 0.2

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+7|=|3x8|
without the absolute value bars:

|x|=|y||2x+7|=|3x8|
x=+y(2x+7)=(3x8)
x=y(2x+7)=(3x8)
+x=y(2x+7)=(3x8)
x=y(2x+7)=(3x8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+7|=|3x8|
x=+y , +x=y(2x+7)=(3x8)
x=y , x=y(2x+7)=(3x8)

2. Solve the two equations for x

10 additional steps

(2x+7)=(3x-8)

Subtract from both sides:

(2x+7)-3x=(3x-8)-3x

Kumpulkan sebutan sejenis:

(2x-3x)+7=(3x-8)-3x

Permudahkan aritmetik:

-x+7=(3x-8)-3x

Kumpulkan sebutan sejenis:

-x+7=(3x-3x)-8

Permudahkan aritmetik:

x+7=8

Subtract from both sides:

(-x+7)-7=-8-7

Permudahkan aritmetik:

x=87

Permudahkan aritmetik:

x=15

Multiply both sides by :

-x·-1=-15·-1

Buang nilai satu:

x=-15·-1

Permudahkan aritmetik:

x=15

10 additional steps

(2x+7)=-(3x-8)

Expand the parentheses:

(2x+7)=-3x+8

Add to both sides:

(2x+7)+3x=(-3x+8)+3x

Kumpulkan sebutan sejenis:

(2x+3x)+7=(-3x+8)+3x

Permudahkan aritmetik:

5x+7=(-3x+8)+3x

Kumpulkan sebutan sejenis:

5x+7=(-3x+3x)+8

Permudahkan aritmetik:

5x+7=8

Subtract from both sides:

(5x+7)-7=8-7

Permudahkan aritmetik:

5x=87

Permudahkan aritmetik:

5x=1

Divide both sides by :

(5x)5=15

Permudahkan pecahan:

x=15

3. List the solutions

x=15,15
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+7|
y=|3x8|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.