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Penyelesaian - Absolute value equations

Hasil Akhir Langkah-langkah Terma dan topik

Exact form:

x = \frac{8}{3}, \frac{2}{7}

x=\frac{8}{3} , \frac{2}{7}

Mixed number form:

x = 2 \frac{2}{3}, \frac{2}{7}

x=2\frac{2}{3} , \frac{2}{7}

Decimal form:

x = 2.667, 0.286

x=2.667 , 0.286

Lihat langkah Learn more with Tiger Try this:

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 2 x + 3 | = 5 | x - 1 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 2 x + 3 \| = 5 \| x - 1 \|$
$x = + y$	$(2 x + 3) = 5 (x - 1)$
$x = - y$	$(2 x + 3) = 5 (- (x - 1))$
$+ x = y$	$(2 x + 3) = 5 (x - 1)$
$- x = y$	$- (2 x + 3) = 5 (x - 1)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 2 x + 3 \| = 5 \| x - 1 \|$
$x = + y$ , $+ x = y$	$(2 x + 3) = 5 (x - 1)$
$x = - y$ , $- x = y$	$(2 x + 3) = 5 (- (x - 1))$

2. Solve the two equations for x

13 additional steps

$(2 x + 3) = 5 \cdot (x - 1)$

Expand the parentheses:

$(2 x + 3) = 5 x + 5 \cdot - 1$

Permudahkan aritmetik:

$(2 x + 3) = 5 x - 5$

Subtract from both sides:

$(2 x + 3) - 5 x = (5 x - 5) - 5 x$

Kumpulkan sebutan sejenis:

$(2 x - 5 x) + 3 = (5 x - 5) - 5 x$

Permudahkan aritmetik:

$- 3 x + 3 = (5 x - 5) - 5 x$

Kumpulkan sebutan sejenis:

$- 3 x + 3 = (5 x - 5 x) - 5$

Permudahkan aritmetik:

$- 3 x + 3 = - 5$

Subtract from both sides:

$(- 3 x + 3) - 3 = - 5 - 3$

Permudahkan aritmetik:

$- 3 x = - 5 - 3$

Permudahkan aritmetik:

$- 3 x = - 8$

Divide both sides by :

$\frac{(- 3 x)}{- 3} = \frac{- 8}{- 3}$

Hapuskan tanda negatif:

$\frac{3 x}{3} = \frac{- 8}{- 3}$

Permudahkan pecahan:

$x = \frac{- 8}{- 3}$

Hapuskan tanda negatif:

$x = \frac{8}{3}$

14 additional steps

$(2 x + 3) = 5 \cdot (- (x - 1))$

Expand the parentheses:

$(2 x + 3) = 5 \cdot (- x + 1)$

$(2 x + 3) = 5 \cdot - x + 5 \cdot 1$

Kumpulkan sebutan sejenis:

$(2 x + 3) = (5 \cdot - 1) x + 5 \cdot 1$

Darabkan pekali:

$(2 x + 3) = - 5 x + 5 \cdot 1$

Permudahkan aritmetik:

$(2 x + 3) = - 5 x + 5$

Add to both sides:

$(2 x + 3) + 5 x = (- 5 x + 5) + 5 x$

Kumpulkan sebutan sejenis:

$(2 x + 5 x) + 3 = (- 5 x + 5) + 5 x$

Permudahkan aritmetik:

$7 x + 3 = (- 5 x + 5) + 5 x$

Kumpulkan sebutan sejenis:

$7 x + 3 = (- 5 x + 5 x) + 5$

Permudahkan aritmetik:

$7 x + 3 = 5$

Subtract from both sides:

$(7 x + 3) - 3 = 5 - 3$

Permudahkan aritmetik:

$7 x = 5 - 3$

Permudahkan aritmetik:

$7 x = 2$

Divide both sides by :

$\frac{(7 x)}{7} = \frac{2}{7}$

Permudahkan pecahan:

$x = \frac{2}{7}$

3. List the solutions

$x = \frac{8}{3}, \frac{2}{7}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 2 x + 3 |$
$y = 5 | x - 1 |$
The equation is true where the two lines cross.

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Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Penyelesaian - Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Mengapa belajar ini

Terma dan topik

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