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Penyelesaian - Absolute value equations

Exact form: x=12,2
x=12 , 2

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+1|=|3x11|
without the absolute value bars:

|x|=|y||2x+1|=|3x11|
x=+y(2x+1)=(3x11)
x=y(2x+1)=(3x11)
+x=y(2x+1)=(3x11)
x=y(2x+1)=(3x11)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+1|=|3x11|
x=+y , +x=y(2x+1)=(3x11)
x=y , x=y(2x+1)=(3x11)

2. Solve the two equations for x

10 additional steps

(2x+1)=(3x-11)

Subtract from both sides:

(2x+1)-3x=(3x-11)-3x

Kumpulkan sebutan sejenis:

(2x-3x)+1=(3x-11)-3x

Permudahkan aritmetik:

-x+1=(3x-11)-3x

Kumpulkan sebutan sejenis:

-x+1=(3x-3x)-11

Permudahkan aritmetik:

x+1=11

Subtract from both sides:

(-x+1)-1=-11-1

Permudahkan aritmetik:

x=111

Permudahkan aritmetik:

x=12

Multiply both sides by :

-x·-1=-12·-1

Buang nilai satu:

x=-12·-1

Permudahkan aritmetik:

x=12

12 additional steps

(2x+1)=-(3x-11)

Expand the parentheses:

(2x+1)=-3x+11

Add to both sides:

(2x+1)+3x=(-3x+11)+3x

Kumpulkan sebutan sejenis:

(2x+3x)+1=(-3x+11)+3x

Permudahkan aritmetik:

5x+1=(-3x+11)+3x

Kumpulkan sebutan sejenis:

5x+1=(-3x+3x)+11

Permudahkan aritmetik:

5x+1=11

Subtract from both sides:

(5x+1)-1=11-1

Permudahkan aritmetik:

5x=111

Permudahkan aritmetik:

5x=10

Divide both sides by :

(5x)5=105

Permudahkan pecahan:

x=105

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

x=(2·5)(1·5)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

x=2

3. List the solutions

x=12,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+1|
y=|3x11|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.