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Penyelesaian - Absolute value equations

Exact form: x=1710
x=\frac{17}{10}
Mixed number form: x=1710
x=1\frac{7}{10}
Decimal form: x=1.7
x=1.7

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|-x+25|=|-x+3|
without the absolute value bars:

|x|=|y||-x+25|=|-x+3|
x=+y(-x+25)=(-x+3)
x=-y(-x+25)=-(-x+3)
+x=y(-x+25)=(-x+3)
-x=y-(-x+25)=(-x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||-x+25|=|-x+3|
x=+y , +x=y(-x+25)=(-x+3)
x=-y , -x=y(-x+25)=-(-x+3)

2. Solve the two equations for x

5 additional steps

(-x+25)=(-x+3)

Add to both sides:

(-x+25)+x=(-x+3)+x

Kumpulkan sebutan sejenis:

(-x+x)+25=(-x+3)+x

Permudahkan aritmetik:

25=(-x+3)+x

Kumpulkan sebutan sejenis:

25=(-x+x)+3

Permudahkan aritmetik:

25=3

Pernyataan ini palsu:

25=3

The equation is false so it has no solution.

18 additional steps

(-x+25)=-(-x+3)

Expand the parentheses:

(-x+25)=x-3

Subtract from both sides:

(-x+25)-x=(x-3)-x

Kumpulkan sebutan sejenis:

(-x-x)+25=(x-3)-x

Permudahkan aritmetik:

-2x+25=(x-3)-x

Kumpulkan sebutan sejenis:

-2x+25=(x-x)-3

Permudahkan aritmetik:

-2x+25=-3

Subtract from both sides:

(-2x+25)-25=-3-25

Gabungkan pecahan:

-2x+(2-2)5=-3-25

Gabungkan pembilang:

-2x+05=-3-25

Permudahkan pembilang sifar:

-2x+0=-3-25

Permudahkan aritmetik:

-2x=-3-25

Tukar nombor bulat kepada pecahan:

-2x=-155+-25

Gabungkan pecahan:

-2x=(-15-2)5

Gabungkan pembilang:

-2x=-175

Divide both sides by :

(-2x)-2=(-175)-2

Hapuskan tanda negatif:

2x2=(-175)-2

Permudahkan pecahan:

x=(-175)-2

Permudahkan aritmetik:

x=-17(5·-2)

x=1710

3. Graph

Each line represents the function of one side of the equation:
y=|-x+25|
y=|-x+3|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.