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Penyelesaian - Absolute value equations

Exact form: b=8
b=8

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|b+14|=|b+2|
without the absolute value bars:

|x|=|y||b+14|=|b+2|
x=+y(b+14)=(b+2)
x=y(b+14)=(b+2)
+x=y(b+14)=(b+2)
x=y(b+14)=(b+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||b+14|=|b+2|
x=+y , +x=y(b+14)=(b+2)
x=y , x=y(b+14)=(b+2)

2. Solve the two equations for b

5 additional steps

(-b+14)=(-b+2)

Add to both sides:

(-b+14)+b=(-b+2)+b

Kumpulkan sebutan sejenis:

(-b+b)+14=(-b+2)+b

Permudahkan aritmetik:

14=(-b+2)+b

Kumpulkan sebutan sejenis:

14=(-b+b)+2

Permudahkan aritmetik:

14=2

Pernyataan ini palsu:

14=2

The equation is false so it has no solution.

14 additional steps

(-b+14)=-(-b+2)

Expand the parentheses:

(-b+14)=b-2

Subtract from both sides:

(-b+14)-b=(b-2)-b

Kumpulkan sebutan sejenis:

(-b-b)+14=(b-2)-b

Permudahkan aritmetik:

-2b+14=(b-2)-b

Kumpulkan sebutan sejenis:

-2b+14=(b-b)-2

Permudahkan aritmetik:

-2b+14=-2

Subtract from both sides:

(-2b+14)-14=-2-14

Permudahkan aritmetik:

-2b=-2-14

Permudahkan aritmetik:

-2b=-16

Divide both sides by :

(-2b)-2=-16-2

Hapuskan tanda negatif:

2b2=-16-2

Permudahkan pecahan:

b=-16-2

Hapuskan tanda negatif:

b=162

Cari faktor sepunya terbesar bagi pembilang dan penyebut:

b=(8·2)(1·2)

Faktorkan keluar dan hapuskan faktor sepunya terbesar:

b=8

3. Graph

Each line represents the function of one side of the equation:
y=|b+14|
y=|b+2|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.