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Penyelesaian - Absolute value equations

Exact form: w=-26,-23
w=-26 , -\frac{2}{3}
Decimal form: w=26,0.667
w=-26 , -0.667

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|12w-6|=|w+7|
without the absolute value bars:

|x|=|y||12w-6|=|w+7|
x=+y(12w-6)=(w+7)
x=-y(12w-6)=-(w+7)
+x=y(12w-6)=(w+7)
-x=y-(12w-6)=(w+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||12w-6|=|w+7|
x=+y , +x=y(12w-6)=(w+7)
x=-y , -x=y(12w-6)=-(w+7)

2. Solve the two equations for w

16 additional steps

(12w-6)=(w+7)

Subtract from both sides:

(12w-6)-w=(w+7)-w

Kumpulkan sebutan sejenis:

(12w-w)-6=(w+7)-w

Kumpulkan pekali:

(12-1)w-6=(w+7)-w

Tukar nombor bulat kepada pecahan:

(12+-22)w-6=(w+7)-w

Gabungkan pecahan:

(1-2)2w-6=(w+7)-w

Gabungkan pembilang:

-12w-6=(w+7)-w

Kumpulkan sebutan sejenis:

-12w-6=(w-w)+7

Permudahkan aritmetik:

-12w-6=7

Add to both sides:

(-12w-6)+6=7+6

Permudahkan aritmetik:

-12w=7+6

Permudahkan aritmetik:

-12w=13

Multiply both sides by inverse fraction :

(-12w)·2-1=13·2-1

Kumpulkan sebutan sejenis:

(-12·-2)w=13·2-1

Darabkan pekali:

(-1·-2)2w=13·2-1

Permudahkan aritmetik:

1w=13·2-1

w=13·2-1

Permudahkan aritmetik:

w=26

16 additional steps

(12w-6)=-(w+7)

Expand the parentheses:

(12w-6)=-w-7

Add to both sides:

(12w-6)+w=(-w-7)+w

Kumpulkan sebutan sejenis:

(12w+w)-6=(-w-7)+w

Kumpulkan pekali:

(12+1)w-6=(-w-7)+w

Tukar nombor bulat kepada pecahan:

(12+22)w-6=(-w-7)+w

Gabungkan pecahan:

(1+2)2w-6=(-w-7)+w

Gabungkan pembilang:

32w-6=(-w-7)+w

Kumpulkan sebutan sejenis:

32w-6=(-w+w)-7

Permudahkan aritmetik:

32w-6=-7

Add to both sides:

(32w-6)+6=-7+6

Permudahkan aritmetik:

32w=-7+6

Permudahkan aritmetik:

32w=-1

Multiply both sides by inverse fraction :

(32w)·23=-1·23

Kumpulkan sebutan sejenis:

(32·23)w=-1·23

Darabkan pekali:

(3·2)(2·3)w=-1·23

Permudahkan pecahan:

w=-1·23

Buang nilai satu:

w=-23

3. List the solutions

w=-26,-23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|12w-6|
y=|w+7|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.