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Penyelesaian - Absolute value equations

Exact form: x=-12,-74
x=-\frac{1}{2} , -\frac{7}{4}
Mixed number form: x=-12,-134
x=-\frac{1}{2} , -1\frac{3}{4}
Decimal form: x=0.5,1.75
x=-0.5 , -1.75

Other Ways to Solve

Absolute value equations

Penjelasan langkah demi langkah

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x4|=|x3|
without the absolute value bars:

|x|=|y||3x4|=|x3|
x=+y(3x4)=(x3)
x=y(3x4)=(x3)
+x=y(3x4)=(x3)
x=y(3x4)=(x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x4|=|x3|
x=+y , +x=y(3x4)=(x3)
x=y , x=y(3x4)=(x3)

2. Solve the two equations for x

11 additional steps

(-3x-4)=(-x-3)

Add to both sides:

(-3x-4)+x=(-x-3)+x

Kumpulkan sebutan sejenis:

(-3x+x)-4=(-x-3)+x

Permudahkan aritmetik:

-2x-4=(-x-3)+x

Kumpulkan sebutan sejenis:

-2x-4=(-x+x)-3

Permudahkan aritmetik:

2x4=3

Add to both sides:

(-2x-4)+4=-3+4

Permudahkan aritmetik:

2x=3+4

Permudahkan aritmetik:

2x=1

Divide both sides by :

(-2x)-2=1-2

Hapuskan tanda negatif:

2x2=1-2

Permudahkan pecahan:

x=1-2

Pindahkan tanda negatif dari penyebut ke pembilang:

x=-12

12 additional steps

(-3x-4)=-(-x-3)

Expand the parentheses:

(-3x-4)=x+3

Subtract from both sides:

(-3x-4)-x=(x+3)-x

Kumpulkan sebutan sejenis:

(-3x-x)-4=(x+3)-x

Permudahkan aritmetik:

-4x-4=(x+3)-x

Kumpulkan sebutan sejenis:

-4x-4=(x-x)+3

Permudahkan aritmetik:

4x4=3

Add to both sides:

(-4x-4)+4=3+4

Permudahkan aritmetik:

4x=3+4

Permudahkan aritmetik:

4x=7

Divide both sides by :

(-4x)-4=7-4

Hapuskan tanda negatif:

4x4=7-4

Permudahkan pecahan:

x=7-4

Pindahkan tanda negatif dari penyebut ke pembilang:

x=-74

3. List the solutions

x=-12,-74
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x4|
y=|x3|
The equation is true where the two lines cross.

Mengapa belajar ini

Learn more with Tiger

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.