सोल्यूशन - भूमितीय अनुक्रम

मालिकेचा सामान्य रूप कसा असेल हे शोधण्यासाठी, पहिला मूळभूत: $$a=105$$ आणि सामान्य अनुपात: $$r=0.02857142857142857$$ या भूतगणितीय मालिकेच्या सूत्रात ठेवा:

$$a_1=105$$

$$a_2=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{2-1}=105\cdot {0.02857142857142857}^1=105\cdot 0.02857142857142857=3$$

$$a_3=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{3-1}=105\cdot {0.02857142857142857}^2=105\cdot 0.0008163265306122448=0.0857142857142857$$

$$a_4=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{4-1}=105\cdot {0.02857142857142857}^3=105\cdot 2.332361516034985E-05=0.0024489795918367346$$

$$a_5=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{5-1}=105\cdot {0.02857142857142857}^4=105\cdot 6.663890045814243E-07=6.997084548104955E-05$$

$$a_6=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{6-1}=105\cdot {0.02857142857142857}^5=105\cdot 1.9039685845183553E-08=1.999167013744273E-06$$

$$a_7=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{7-1}=105\cdot {0.02857142857142857}^6=105\cdot 5.439910241481015E-10=5.7119057535550655E-08$$

$$a_8=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{8-1}=105\cdot {0.02857142857142857}^7=105\cdot 1.5542600689945756E-11=1.6319730724443044E-09$$

$$a_9=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{9-1}=105\cdot {0.02857142857142857}^8=105\cdot 4.440743054270216E-13=4.6627802069837265E-11$$

$$a_{10}=a_1·r^{n-1}=105\cdot {0.02857142857142857}^{10-1}=105\cdot {0.02857142857142857}^9=105\cdot 1.2687837297914902E-14=1.3322229162810648E-12$$