सोल्यूशन - भूमितीय अनुक्रम

मालिकेचा सामान्य रूप कसा असेल हे शोधण्यासाठी, पहिला मूळभूत: $$a=42$$ आणि सामान्य अनुपात: $$r=2.1904761904761907$$ या भूतगणितीय मालिकेच्या सूत्रात ठेवा:

$$a_1=42$$

$$a_2=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{2-1}=42\cdot {2.1904761904761907}^1=42\cdot 2.1904761904761907=92.00000000000001$$

$$a_3=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{3-1}=42\cdot {2.1904761904761907}^2=42\cdot 4.7981859410430845=201.52380952380955$$

$$a_4=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{4-1}=42\cdot {2.1904761904761907}^3=42\cdot 10.510312061332472=441.43310657596385$$

$$a_5=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{5-1}=42\cdot {2.1904761904761907}^4=42\cdot 23.022588324823513=966.9487096425876$$

$$a_6=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{6-1}=42\cdot {2.1904761904761907}^5=42\cdot 50.430431568661035=2118.0781258837633$$

$$a_7=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{7-1}=42\cdot {2.1904761904761907}^6=42\cdot 110.46665962659085=4639.599704316815$$

$$a_8=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{8-1}=42\cdot {2.1904761904761907}^7=42\cdot 241.97458775348474=10162.93268564636$$

$$a_9=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{9-1}=42\cdot {2.1904761904761907}^8=42\cdot 530.0395731742999=22261.662073320596$$

$$a_{10}=a_1·r^{n-1}=42\cdot {2.1904761904761907}^{10-1}=42\cdot {2.1904761904761907}^9=42\cdot 1161.0390650484667=48763.6407320356$$