सोल्यूशन - भूमितीय अनुक्रम

मालिकेचा सामान्य रूप कसा असेल हे शोधण्यासाठी, पहिला मूळभूत: $$a=42$$ आणि सामान्य अनुपात: $$r=0.19047619047619047$$ या भूतगणितीय मालिकेच्या सूत्रात ठेवा:

$$a_1=42$$

$$a_2=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{2-1}=42\cdot {0.19047619047619047}^1=42\cdot 0.19047619047619047=8$$

$$a_3=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{3-1}=42\cdot {0.19047619047619047}^2=42\cdot 0.03628117913832199=1.5238095238095235$$

$$a_4=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{4-1}=42\cdot {0.19047619047619047}^3=42\cdot 0.006910700788251807=0.2902494331065759$$

$$a_5=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{5-1}=42\cdot {0.19047619047619047}^4=42\cdot 0.0013163239596670109=0.05528560630601446$$

$$a_6=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{6-1}=42\cdot {0.19047619047619047}^5=42\cdot 0.0002507283732699068=0.010530591677336087$$

$$a_7=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{7-1}=42\cdot {0.19047619047619047}^6=42\cdot 4.7757785384744155E-05=0.0020058269861592546$$

$$a_8=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{8-1}=42\cdot {0.19047619047619047}^7=42\cdot 9.096721025665552E-06=0.0003820622830779532$$

$$a_9=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{9-1}=42\cdot {0.19047619047619047}^8=42\cdot 1.7327087667934384E-06=7.277376820532442E-05$$

$$a_{10}=a_1·r^{n-1}=42\cdot {0.19047619047619047}^{10-1}=42\cdot {0.19047619047619047}^9=42\cdot 3.300397651035121E-07=1.3861670134347507E-05$$