해결방법 - 타이거 알지브라 해결기

$${\left(4D6\right)}_{16}$$

단계: $$4·{16}^2$$
+ $$13·{16}^1$$
+ $$6·{16}^0$$ = $$1,238$$.

$$4\cdot {16}^2+13\cdot {16}^1+6\cdot {16}^0$$

단계: $$4·{16}^2$$
+ $$13·{16}^1$$
+ $$6·{16}^0$$ = $$1,238$$.

$$1238$$

단계: $$4·{16}^2$$
+ $$13·{16}^1$$
+ $$6·{16}^0$$ = $$1,238$$.

$$1238\left(base10\right)$$

$$1,{238}_{10}=1,{238}_{10}$$.

$$\frac{1238}{10}$$

$$1,{238}_{10}=1,{238}_{10}$$.

$$1238=10\cdot 123+8$$

$$1,{238}_{10}=1,{238}_{10}$$.

$$123=10\cdot 12+3$$

$$1,{238}_{10}=1,{238}_{10}$$.

$$12=10\cdot 1+2$$

$$1,{238}_{10}=1,{238}_{10}$$.

$$1=10\cdot 0+1$$

$$1,{238}_{10}=1,{238}_{10}$$.

$$1238$$

$$1,{238}_{10}=1,{238}_{10}$$.

$${\left(1238\right)}_{10}$$

$$1,{238}_{10}=1,{238}_{10}$$.