解答 - 二点間の距離

ポイント1の座標は:
$$X=$$$$68$$
$$Y=$$$$-15$$
$$P_1\left(x_1=68,y_1=-15\right)$$

ポイント2の座標は:
$$X=$$$$44$$
$$Y=$$$$56$$
$$P_2\left(x_2=44,y_2=56\right)$$

d は二つの点間の距離です。

$$d^2={\left(X_2-X_1\right)}^2+{\left(Y_2-Y_1\right)}^2$$

$$d=\sqrt{\left({\left(X_2-X_1\right)}^2+{\left(Y_2-Y_1\right)}^2\right)}$$

$$d=\sqrt{\left({\left(X_2-68\right)}^2+{\left(Y_2-Y_1\right)}^2\right)}$$

$$d=\sqrt{\left({\left(44-68\right)}^2+{\left(Y_2-Y_1\right)}^2\right)}$$

$$d=\sqrt{\left({\left(44-68\right)}^2+{\left(Y_2--15\right)}^2\right)}$$

$$d=\sqrt{\left({\left(44-68\right)}^2+{\left(56--15\right)}^2\right)}$$

$$d=\sqrt{\left({\left(-24\right)}^2+{\left(56--15\right)}^2\right)}$$

$$d=\sqrt{\left({\left(-24\right)}^2+{\left(71\right)}^2\right)}$$

$$d=\sqrt{\left(576+{\left(71\right)}^2\right)}$$

$$d=\sqrt{\left(576+5041\right)}$$

$$d=\sqrt{\left(5617\right)}$$

$$d=74.947$$