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Solusi - Probabilitas kumulatif dalam distribusi normal standar

Cumulative probability 351400%
-351400%

Penjelasan langkah demi langkah

1. Find the cumulative probability of the z-scores values up to 1.812

Usa la tabla z negativa para encontrar el valor correspondiente a 1,812. Este valor es la probabilidad acumulativa del área a la izquierda de 1,812.

Z0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
-3,95544444433
-3,87776666555
-3,711111998888
-3,616151514141313121211
-3,52322222121919181717
-3,43432313292827262524
-3,34847454342439383635
-3,2696664626585654525
-3,19794987848279767471
-3,01351311261221181141111071041
-2,9187181175169164159154149144139
-2,825624824233226219212205199193
-2,734733632631730729828928272264
-2,646645344427415402391379368357
-2,56216045875755453952350849448
-2,482798776755734714695676657639
-2,310721044101799964939914889866842
-2,21391355132112871255122211911161131101
-2,1178617431716591618157815391514631426
-2,0227522222169211820682018197192318761831
-1,9287228072743268261925592524422385233
-1,83593351534383362328832163144307430052938
-1,7445743634272418240934006392383637543673
-1,65485375262515550549474846474646484551
-1,56681655264266301617860575938582157055592
-1,4807679277787636749373537215707869446811
-1,396895193429176901288518692853483798226
-1,21150711314111231093510749105651038310204100279853
-1,1135671335131361292412714125071230212111911702
-1,015866156251538615151149171468614457142311400713786
-0,918406181411787917619173611710616853166021635416109
-0,821186208972061120327200451976619489192151894318673
-0,7241962388523576232722965226632236322065217721476
-0,62742527093267632643526109257852546325143248252451
-0,5308543050330153298062946291162877428434280962776
-0,4344583409337243336329973263632276319183156131207
-0,33820937828374483707366933631735942355693519734827
-0,242074416834129440905405174012939743393583897438591
-0,14601745624522444828444334403843644432514285842465
0,0549601492024880348405480064760847214681246414

Un puntaje z de 1,812 corresponde a un área de 3,515
p(z<1,812)=3,515
La probabilidad acumulativa de que z<1,812 sea 351500%

2. Find the cumulative probability for the z-scores values greater than 1.812

To find the cumulative probability of the values greater than 1,812, we need to subtract the cumulative probability of the values less than 1,812 from the total probability under the curve, which is equal to 1:

13,515=3514
p(z>1,812)=3514
The cumulative probability of z>1,812 is 351400%

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