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Solusi - Probabilitas kumulatif dalam distribusi normal standar

Cumulative probability 400%
-400%

Penjelasan langkah demi langkah

1. Find the cumulative probability of the z-scores values up to 22.37

Más del 99,9% del tiempo, los datos con una distribución normal estándar se encuentran dentro de más o menos 3,9 desviaciones estándar de la media.

La probabilidad acumulativa de los valores hasta 22,37 es 1.
p(z<22,37)=1
La probabilidad acumulativa de que z<22,37 sea 100%

2. Find the cumulative probability of the z-scores values up to 0

Use the positive or negative z-table to find the value corresponding to 0. This value is the cumulative probability of the area to the left of 0.

Z0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
0,0550399507985119751595519945239252795318853586
0,15398354385477655172555675596256356567495714257535
0,257926583175870659095594835987160257606426102661409
0,36179162172625526293633076368364058644316480365173
0,4655426591662766664670036736467724680826843968793
0,5691466949769847701947054708847122671566719047224
0,67257572907732377356573891742157453774857751757549
0,7758047611576424767377035773377763777935782378524
0,878814791037938979673799558023480511807858105781327
0,981594818598212182381826398289483147833988364683891
1,084134843758461484849850838531485543857698599386214
1,1864338665868648707687286874938769887988188298
1,288493886868887789065892518943589617897968997390147
1,3903290499065890824909889114991308914669162191774
1,49192492073922292364925079264792785929229305693189
1,593319934489357493699938229394394062941799429594408
1,694529463947389484594959505395154952549535295449
1,79554395637957289581895907959949608961649624696327
1,896407964859656296638967129678496856969269699597062
1,99712897193972579732973819744197597558976159767
2,09772597778978319788297932979829803980779812498169
2,19821498257983983419838298422984619859853798574
2,298619864598679987139874598778988099884988798899
2,39892898956989839901990369906199086991119913499158
2,49918992029922499245992669928699305993249934399361
2,5993799939699413994399446994619947799492995069952
2,69953499547995699573995859959899609996219963299643
2,79965399664996749968399693997029971199729972899736
2,89974499752997699767997749978199788997959980199807
2,999813998199982599831998369984199846998519985699861
3,0998659986999874998789988299886998899989399896999
3,19990399906999199913999169991899921999249992699929
3,2999319993499936999389994999429994499946999489995
3,39995299953999559995799958999699961999629996499965
3,49996699968999699997999719997299973999749997599976
3,59997799978999789997999989998199981999829998399983
3,699984999859998599986999869998799987999889998899989
3,799989999999999999999919999199992999929999299992
3,899993999939999399994999949999499994999959999599995
3,999995999959999699996999969999699996999969999799997

A z-score of 0 corresponds to an area of 0,50000
p(z<0)=0,50000
The cumulative probability that z<0 is 50%

3. Calculate the cumulative probability between 22.37 and 0

To find the cumulative probability of the area between the two z-scores, subtract the smaller cumulative probability (everything to the left of 0) from the larger cumulative probability (everything to the left of 22,37):

1-5=-4
p(0<z<22,37)=-4
The cumulative probability that 0<z<22,37 is -400%

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