Solusi - Pertidaksamaan linear dengan satu variabel tidak diketahui

$$\left(\frac{x}{3}+\frac{-1}{4}\right)-\frac{x}{4}<\left(\frac{x}{4}+1\right)-\frac{x}{4}$$

Kelompokkan suku sejenis:

$$\left(\frac{x}{3}+\frac{-1}{4}x\right)+\frac{-1}{4}<\left(\frac{x}{4}+1\right)-\frac{x}{4}$$

Kelompokkan koefisien-koefisien:

$$\left(\frac{1}{3}+\frac{-1}{4}\right)x+\frac{-1}{4}<\left(\frac{x}{4}+1\right)-\frac{x}{4}$$

Tentukan penyebut terkecil:

$$\left(\frac{\left(1·4\right)}{\left(3·4\right)}+\frac{\left(-1·3\right)}{\left(4·3\right)}\right)x+\frac{-1}{4}<\left(\frac{x}{4}+1\right)-\frac{x}{4}$$

Kalikan penyebut:

$$\left(\frac{\left(1·4\right)}{12}+\frac{\left(-1·3\right)}{12}\right)x+\frac{-1}{4}<\left(\frac{x}{4}+1\right)-\frac{x}{4}$$

Kalikan pembilang:

$$\left(\frac{4}{12}+\frac{-3}{12}\right)x+\frac{-1}{4}<\left(\frac{x}{4}+1\right)-\frac{x}{4}$$

Gabungkan pecahan:

$$\frac{\left(4-3\right)}{12}x+\frac{-1}{4}<\left(\frac{x}{4}+1\right)-\frac{x}{4}$$

Gabungkan pembilang:

$$\frac{1}{12}x+\frac{-1}{4}<\left(\frac{x}{4}+1\right)-\frac{x}{4}$$

Kelompokkan suku sejenis:

$$\frac{1}{12}·x+\frac{-1}{4}<\left(\frac{x}{4}+\frac{-1}{4}x\right)+1$$

Gabungkan pecahan:

$$\frac{1}{12}·x+\frac{-1}{4}<\frac{\left(1-1\right)}{4}x+1$$

Gabungkan pembilang:

$$\frac{1}{12}·x+\frac{-1}{4}<\frac{0}{4}x+1$$

Pengurangan pembilang nol:

$$\frac{1}{12}x+\frac{-1}{4}<0x+1$$

Sederhanakan hitungan:

$$\frac{1}{12}x+\frac{-1}{4}<1$$