Solusi - Pemecah Soal Tiger Algebra

$${\left(BE\right)}_{16}$$

Langkah: $$11·{16}^1$$
+ $$14·{16}^0$$ = $$190$$.

$$11\cdot {16}^1+14\cdot {16}^0$$

Langkah: $$11·{16}^1$$
+ $$14·{16}^0$$ = $$190$$.

$$190$$

Langkah: $$11·{16}^1$$
+ $$14·{16}^0$$ = $$190$$.

$$190\left(base10\right)$$

$${190}_{10}={190}_{10}$$.

$$\frac{190}{10}$$

$${190}_{10}={190}_{10}$$.

$$190=10\cdot 19+0$$

$${190}_{10}={190}_{10}$$.

$$19=10\cdot 1+9$$

$${190}_{10}={190}_{10}$$.

$$1=10\cdot 0+1$$

$${190}_{10}={190}_{10}$$.

$$190$$

$${190}_{10}={190}_{10}$$.

$${\left(190\right)}_{10}$$

$${190}_{10}={190}_{10}$$.