Step by Step Solution
Step by step solution :
Step 1 :
Trying to factor as a Difference of Cubes:
 1.1      Factoring:  x3-20 
 Theory : A difference of two perfect cubes,  a3 - b3  can be factored into
              (a-b) • (a2 +ab +b2)
Proof :  (a-b)•(a2+ab+b2) =
            a3+a2b+ab2-ba2-b2a-b3 =
            a3+(a2b-ba2)+(ab2-b2a)-b3 =
            a3+0+0-b3 =
            a3-b3
Check :  20  is not a cube !! 
Ruling : Binomial can not be factored as the difference of two perfect cubes
Polynomial Roots Calculator :
 1.2    Find roots (zeroes) of :       F(x) = x3-20
Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient
In this case, the Leading Coefficient is  1  and the Trailing Constant is  -20. 
 The factor(s) are: 
of the Leading Coefficient :  1
 of the Trailing Constant :  1 ,2 ,4 ,5 ,10 ,20 
 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | -21.00 | ||||||
| -2 | 1 | -2.00 | -28.00 | ||||||
| -4 | 1 | -4.00 | -84.00 | ||||||
| -5 | 1 | -5.00 | -145.00 | ||||||
| -10 | 1 | -10.00 | -1020.00 | ||||||
| -20 | 1 | -20.00 | -8020.00 | ||||||
| 1 | 1 | 1.00 | -19.00 | ||||||
| 2 | 1 | 2.00 | -12.00 | ||||||
| 4 | 1 | 4.00 | 44.00 | ||||||
| 5 | 1 | 5.00 | 105.00 | ||||||
| 10 | 1 | 10.00 | 980.00 | ||||||
| 20 | 1 | 20.00 | 7980.00 | 
Polynomial Roots Calculator found no rational roots 
Equation at the end of step 1 :
  x3 - 20  = 0 
Step 2 :
Solving a Single Variable Equation :
 2.1      Solve  :    x3-20 = 0 
 Add  20  to both sides of the equation : 
                      x3 = 20 
When two things are equal, their cube roots are equal. Taking the cube root of the two sides of the equation we get:  
                      x  =  ∛ 20  
 The equation has one real solution
This solution is  x = ∛20  = 2.7144 
One solution was found :
x = ∛20 = 2.7144How did we do?
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