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Solusyon - Pangkabuuang probabilidad sa standard normal na distribusyon

Pangkabuuang probabilidad 98.422%
98.422%

Hakbang-sa-hakbang na paliwanag

1. Alamin ang pangkabuuang probabilidad ng mga halaga ng z-score hanggang sa 2.153

Gamitin ang negatibong z-table upang mahanap ang katumbas na halaga para sa 2.153. Ang halagang ito ang nakuha peluang ng lugar ng sa kaliwang bahagi ng 2.153.

Z0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
-3.90.000050.000050.000040.000040.000040.000040.000040.000040.000030.00003
-3.80.000070.000070.000070.000060.000060.000060.000060.000050.000050.00005
-3.70.000110.00010.00010.00010.000090.000090.000080.000080.000080.00008
-3.60.000160.000150.000150.000140.000140.000130.000130.000120.000120.00011
-3.50.000230.000220.000220.000210.00020.000190.000190.000180.000170.00017
-3.40.000340.000320.000310.00030.000290.000280.000270.000260.000250.00024
-3.30.000480.000470.000450.000430.000420.00040.000390.000380.000360.00035
-3.20.000690.000660.000640.000620.00060.000580.000560.000540.000520.0005
-3.10.000970.000940.00090.000870.000840.000820.000790.000760.000740.00071
-3.00.001350.001310.001260.001220.001180.001140.001110.001070.001040.001
-2.90.001870.001810.001750.001690.001640.001590.001540.001490.001440.00139
-2.80.002560.002480.00240.002330.002260.002190.002120.002050.001990.00193
-2.70.003470.003360.003260.003170.003070.002980.002890.00280.002720.00264
-2.60.004660.004530.00440.004270.004150.004020.003910.003790.003680.00357
-2.50.006210.006040.005870.00570.005540.005390.005230.005080.004940.0048
-2.40.00820.007980.007760.007550.007340.007140.006950.006760.006570.00639
-2.30.010720.010440.010170.00990.009640.009390.009140.008890.008660.00842
-2.20.01390.013550.013210.012870.012550.012220.011910.01160.01130.01101
-2.10.017860.017430.0170.016590.016180.015780.015390.0150.014630.01426
-2.00.022750.022220.021690.021180.020680.020180.01970.019230.018760.01831
-1.90.028720.028070.027430.02680.026190.025590.0250.024420.023850.0233
-1.80.035930.035150.034380.033620.032880.032160.031440.030740.030050.02938
-1.70.044570.043630.042720.041820.040930.040060.03920.038360.037540.03673
-1.60.05480.05370.052620.051550.05050.049470.048460.047460.046480.04551
-1.50.066810.065520.064260.063010.061780.060570.059380.058210.057050.05592
-1.40.080760.079270.07780.076360.074930.073530.072150.070780.069440.06811
-1.30.09680.09510.093420.091760.090120.088510.086920.085340.083790.08226
-1.20.115070.113140.111230.109350.107490.105650.103830.102040.100270.09853
-1.10.135670.13350.131360.129240.127140.125070.123020.1210.1190.11702
-1.00.158660.156250.153860.151510.149170.146860.144570.142310.140070.13786
-0.90.184060.181410.178790.176190.173610.171060.168530.166020.163540.16109
-0.80.211860.208970.206110.203270.200450.197660.194890.192150.189430.18673
-0.70.241960.238850.235760.23270.229650.226630.223630.220650.21770.21476
-0.60.274250.270930.267630.264350.261090.257850.254630.251430.248250.2451
-0.50.308540.305030.301530.298060.29460.291160.287740.284340.280960.2776
-0.40.344580.34090.337240.33360.329970.326360.322760.319180.315610.31207
-0.30.382090.378280.374480.37070.366930.363170.359420.355690.351970.34827
-0.20.420740.416830.412940.409050.405170.401290.397430.393580.389740.38591
-0.10.460170.45620.452240.448280.444330.440380.436440.432510.428580.42465
0.00.50.496010.492020.488030.484050.480060.476080.47210.468120.46414

Ang z-score ng 2.153 nakatugma sa lugar ng 0.01578
p(z<2.153)=0.01578
Ang nakuha peluang na z<2.153 ay 1.578%

2. Alamin ang pangkabuuang probabilidad para sa mga halaga ng z-score na higit pa sa 2.153

Upang malaman ang pangkabuuang probabilidad ng mga halaga na higit sa 2.153, kinakailangan natin na ibawas ang pangkabuuang probabilidad ng mga halagang mas mababa sa 2.153 mula sa kabuuang probabilidad sa ilalim ng curve, na katumbas ng 1:

10.01578=0.98422
p(z>2.153)=0.98422
Ang pangkabuuang probabilidad ng z>2.153 ay 98.422%

Bakit kailangan matutuhan ito

Bakit matutunan ito