Solusyon - Tiger Algebra Solver

$${\left(3C4\right)}_{16}$$

Hakbang: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$4·{16}^0$$ = $$964$$.

$$3\cdot {16}^2+12\cdot {16}^1+4\cdot {16}^0$$

Hakbang: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$4·{16}^0$$ = $$964$$.

$$964$$

Hakbang: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$4·{16}^0$$ = $$964$$.

$$964\left(base10\right)$$

$${964}_{10}={964}_{10}$$.

$$\frac{964}{10}$$

$${964}_{10}={964}_{10}$$.

$$964=10\cdot 96+4$$

$${964}_{10}={964}_{10}$$.

$$96=10\cdot 9+6$$

$${964}_{10}={964}_{10}$$.

$$9=10\cdot 0+9$$

$${964}_{10}={964}_{10}$$.

$$964$$

$${964}_{10}={964}_{10}$$.

$${\left(964\right)}_{10}$$

$${964}_{10}={964}_{10}$$.