Solusyon - Tiger Algebra Solver

$${\left(3B0\right)}_{16}$$

Hakbang: $$3·{16}^2$$
+ $$11·{16}^1$$
+ $$0·{16}^0$$ = $$944$$.

$$3\cdot {16}^2+11\cdot {16}^1+0\cdot {16}^0$$

Hakbang: $$3·{16}^2$$
+ $$11·{16}^1$$
+ $$0·{16}^0$$ = $$944$$.

$$944$$

Hakbang: $$3·{16}^2$$
+ $$11·{16}^1$$
+ $$0·{16}^0$$ = $$944$$.

$$944\left(base10\right)$$

$${944}_{10}={944}_{10}$$.

$$\frac{944}{10}$$

$${944}_{10}={944}_{10}$$.

$$944=10\cdot 94+4$$

$${944}_{10}={944}_{10}$$.

$$94=10\cdot 9+4$$

$${944}_{10}={944}_{10}$$.

$$9=10\cdot 0+9$$

$${944}_{10}={944}_{10}$$.

$$944$$

$${944}_{10}={944}_{10}$$.

$${\left(944\right)}_{10}$$

$${944}_{10}={944}_{10}$$.