Solusyon - Tiger Algebra Solver

$${\left(1C6\right)}_{16}$$

Hakbang: $$1·{16}^2$$
+ $$12·{16}^1$$
+ $$6·{16}^0$$ = $$454$$.

$$1\cdot {16}^2+12\cdot {16}^1+6\cdot {16}^0$$

Hakbang: $$1·{16}^2$$
+ $$12·{16}^1$$
+ $$6·{16}^0$$ = $$454$$.

$$454$$

Hakbang: $$1·{16}^2$$
+ $$12·{16}^1$$
+ $$6·{16}^0$$ = $$454$$.

$$454\left(base10\right)$$

$${454}_{10}={454}_{10}$$.

$$\frac{454}{10}$$

$${454}_{10}={454}_{10}$$.

$$454=10\cdot 45+4$$

$${454}_{10}={454}_{10}$$.

$$45=10\cdot 4+5$$

$${454}_{10}={454}_{10}$$.

$$4=10\cdot 0+4$$

$${454}_{10}={454}_{10}$$.

$$454$$

$${454}_{10}={454}_{10}$$.

$${\left(454\right)}_{10}$$

$${454}_{10}={454}_{10}$$.