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Solution - Simplification or other simple results

6(n13+1)(n131)
6*(n^13+1)*(n^13-1)

Step by Step Solution

Step  1  :

Equation at the end of step  1  :

  ((2•3n25) • n) -  6

Step  2  :

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   6n26 - 6  =   6 • (n26 - 1) 

Trying to factor as a Difference of Squares :

 3.2      Factoring:  n26 - 1 

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 - AB + AB - B2 =
         A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1
Check :  n26  is the square of  n13 

Factorization is :       (n13 + 1)  •  (n13 - 1) 

Final result :

  6 • (n13 + 1) • (n13 - 1)

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