Solution - Factoring binomials using the difference of squares
Other Ways to Solve
Factoring binomials using the difference of squaresStep by Step Solution
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
-x27 - 8 = -1 • (x27 + 8)
Trying to factor as a Sum of Cubes :
2.2 Factoring: x27 + 8
Theory : A sum of two perfect cubes, a3 + b3 can be factored into :
(a+b) • (a2-ab+b2)
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
Check : 8 is the cube of 2
Check : x27 is the cube of x9
Factorization is :
(x9 + 2) • (x18 - 2x9 + 4)
Trying to factor as a Sum of Cubes :
2.3 Factoring: x9 + 2
Check : 2 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Polynomial Roots Calculator :
2.4 Find roots (zeroes) of : F(x) = x9 + 2
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is 2.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 1.00 | ||||||
| -2 | 1 | -2.00 | -510.00 | ||||||
| 1 | 1 | 1.00 | 3.00 | ||||||
| 2 | 1 | 2.00 | 514.00 |
Polynomial Roots Calculator found no rational roots
Trying to factor by splitting the middle term
2.5 Factoring x18 - 2x9 + 4
The first term is, x18 its coefficient is 1 .
The middle term is, -2x9 its coefficient is -2 .
The last term, "the constant", is +4
Step-1 : Multiply the coefficient of the first term by the constant 1 • 4 = 4
Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is -2 .
| -4 | + | -1 | = | -5 | ||
| -2 | + | -2 | = | -4 | ||
| -1 | + | -4 | = | -5 | ||
| 1 | + | 4 | = | 5 | ||
| 2 | + | 2 | = | 4 | ||
| 4 | + | 1 | = | 5 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
(-x9 - 2) • (x18 - 2x9 + 4)
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