Solución - Tiger Algebra Solver

$${\left(FFA\right)}_{16}$$

Pasos: $$15·{16}^2$$
+ $$15·{16}^1$$
+ $$10·{16}^0$$ = $$4.090$$.

$$15\cdot {16}^2+15\cdot {16}^1+10\cdot {16}^0$$

Pasos: $$15·{16}^2$$
+ $$15·{16}^1$$
+ $$10·{16}^0$$ = $$4.090$$.

$$4090$$

Pasos: $$15·{16}^2$$
+ $$15·{16}^1$$
+ $$10·{16}^0$$ = $$4,090$$.

$$4090\left(base10\right)$$

$${4.090}_{10}={4.090}_{10}$$.

$$\frac{4090}{10}$$

$${4.090}_{10}={4.090}_{10}$$.

$$4090=10\cdot 409+0$$

$${4.090}_{10}={4.090}_{10}$$.

$$409=10\cdot 40+9$$

$${4.090}_{10}={4.090}_{10}$$.

$$40=10\cdot 4+0$$

$${4.090}_{10}={4.090}_{10}$$.

$$4=10\cdot 0+4$$

$${4.090}_{10}={4.090}_{10}$$.

$$4090$$

$${4.090}_{10}={4.090}_{10}$$.

$${\left(4090\right)}_{10}$$

$$4,{090}_{10}=4,{090}_{10}$$.