Solución - Tiger Algebra Solver

$${\left(FEA\right)}_{16}$$

Pasos: $$15·{16}^2$$
+ $$14·{16}^1$$
+ $$10·{16}^0$$ = $$4.074$$.

$$15\cdot {16}^2+14\cdot {16}^1+10\cdot {16}^0$$

Pasos: $$15·{16}^2$$
+ $$14·{16}^1$$
+ $$10·{16}^0$$ = $$4.074$$.

$$4074$$

Pasos: $$15·{16}^2$$
+ $$14·{16}^1$$
+ $$10·{16}^0$$ = $$4,074$$.

$$4074\left(base10\right)$$

$${4.074}_{10}={4.074}_{10}$$.

$$\frac{4074}{10}$$

$${4.074}_{10}={4.074}_{10}$$.

$$4074=10\cdot 407+4$$

$${4.074}_{10}={4.074}_{10}$$.

$$407=10\cdot 40+7$$

$${4.074}_{10}={4.074}_{10}$$.

$$40=10\cdot 4+0$$

$${4.074}_{10}={4.074}_{10}$$.

$$4=10\cdot 0+4$$

$${4.074}_{10}={4.074}_{10}$$.

$$4074$$

$${4.074}_{10}={4.074}_{10}$$.

$${\left(4074\right)}_{10}$$

$$4,{074}_{10}=4,{074}_{10}$$.