Solución - Tiger Algebra Solver

$${\left(DFA\right)}_{16}$$

Pasos: $$13·{16}^2$$
+ $$15·{16}^1$$
+ $$10·{16}^0$$ = $$3.578$$.

$$13\cdot {16}^2+15\cdot {16}^1+10\cdot {16}^0$$

Pasos: $$13·{16}^2$$
+ $$15·{16}^1$$
+ $$10·{16}^0$$ = $$3.578$$.

$$3578$$

Pasos: $$13·{16}^2$$
+ $$15·{16}^1$$
+ $$10·{16}^0$$ = $$3,578$$.

$$3578\left(base10\right)$$

$${3.578}_{10}={3.578}_{10}$$.

$$\frac{3578}{10}$$

$${3.578}_{10}={3.578}_{10}$$.

$$3578=10\cdot 357+8$$

$${3.578}_{10}={3.578}_{10}$$.

$$357=10\cdot 35+7$$

$${3.578}_{10}={3.578}_{10}$$.

$$35=10\cdot 3+5$$

$${3.578}_{10}={3.578}_{10}$$.

$$3=10\cdot 0+3$$

$${3.578}_{10}={3.578}_{10}$$.

$$3578$$

$${3.578}_{10}={3.578}_{10}$$.

$${\left(3578\right)}_{10}$$

$$3,{578}_{10}=3,{578}_{10}$$.