Solución - Tiger Algebra Solver

$${\left(DED\right)}_{16}$$

Pasos: $$13·{16}^2$$
+ $$14·{16}^1$$
+ $$13·{16}^0$$ = $$3.565$$.

$$13\cdot {16}^2+14\cdot {16}^1+13\cdot {16}^0$$

Pasos: $$13·{16}^2$$
+ $$14·{16}^1$$
+ $$13·{16}^0$$ = $$3.565$$.

$$3565$$

Pasos: $$13·{16}^2$$
+ $$14·{16}^1$$
+ $$13·{16}^0$$ = $$3,565$$.

$$3565\left(base10\right)$$

$${3.565}_{10}={3.565}_{10}$$.

$$\frac{3565}{10}$$

$${3.565}_{10}={3.565}_{10}$$.

$$3565=10\cdot 356+5$$

$${3.565}_{10}={3.565}_{10}$$.

$$356=10\cdot 35+6$$

$${3.565}_{10}={3.565}_{10}$$.

$$35=10\cdot 3+5$$

$${3.565}_{10}={3.565}_{10}$$.

$$3=10\cdot 0+3$$

$${3.565}_{10}={3.565}_{10}$$.

$$3565$$

$${3.565}_{10}={3.565}_{10}$$.

$${\left(3565\right)}_{10}$$

$$3,{565}_{10}=3,{565}_{10}$$.