Solución - Tiger Algebra Solver

$${\left(DCA\right)}_{16}$$

Pasos: $$13·{16}^2$$
+ $$12·{16}^1$$
+ $$10·{16}^0$$ = $$3.530$$.

$$13\cdot {16}^2+12\cdot {16}^1+10\cdot {16}^0$$

Pasos: $$13·{16}^2$$
+ $$12·{16}^1$$
+ $$10·{16}^0$$ = $$3.530$$.

$$3530$$

Pasos: $$13·{16}^2$$
+ $$12·{16}^1$$
+ $$10·{16}^0$$ = $$3,530$$.

$$3530\left(base10\right)$$

$${3.530}_{10}={3.530}_{10}$$.

$$\frac{3530}{10}$$

$${3.530}_{10}={3.530}_{10}$$.

$$3530=10\cdot 353+0$$

$${3.530}_{10}={3.530}_{10}$$.

$$353=10\cdot 35+3$$

$${3.530}_{10}={3.530}_{10}$$.

$$35=10\cdot 3+5$$

$${3.530}_{10}={3.530}_{10}$$.

$$3=10\cdot 0+3$$

$${3.530}_{10}={3.530}_{10}$$.

$$3530$$

$${3.530}_{10}={3.530}_{10}$$.

$${\left(3530\right)}_{10}$$

$$3,{530}_{10}=3,{530}_{10}$$.