Solución - Tiger Algebra Solver

$${\left(BAD\right)}_{16}$$

Pasos: $$11·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$2.989$$.

$$11\cdot {16}^2+10\cdot {16}^1+13\cdot {16}^0$$

Pasos: $$11·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$2.989$$.

$$2989$$

Pasos: $$11·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$2,989$$.

$$2989\left(base10\right)$$

$${2.989}_{10}={2.989}_{10}$$.

$$\frac{2989}{10}$$

$${2.989}_{10}={2.989}_{10}$$.

$$2989=10\cdot 298+9$$

$${2.989}_{10}={2.989}_{10}$$.

$$298=10\cdot 29+8$$

$${2.989}_{10}={2.989}_{10}$$.

$$29=10\cdot 2+9$$

$${2.989}_{10}={2.989}_{10}$$.

$$2=10\cdot 0+2$$

$${2.989}_{10}={2.989}_{10}$$.

$$2989$$

$${2.989}_{10}={2.989}_{10}$$.

$${\left(2989\right)}_{10}$$

$$2,{989}_{10}=2,{989}_{10}$$.