Solución - Tiger Algebra Solver

$${\left(AFE\right)}_{16}$$

Pasos: $$10·{16}^2$$
+ $$15·{16}^1$$
+ $$14·{16}^0$$ = $$2.814$$.

$$10\cdot {16}^2+15\cdot {16}^1+14\cdot {16}^0$$

Pasos: $$10·{16}^2$$
+ $$15·{16}^1$$
+ $$14·{16}^0$$ = $$2.814$$.

$$2814$$

Pasos: $$10·{16}^2$$
+ $$15·{16}^1$$
+ $$14·{16}^0$$ = $$2,814$$.

$$2814\left(base10\right)$$

$${2.814}_{10}={2.814}_{10}$$.

$$\frac{2814}{10}$$

$${2.814}_{10}={2.814}_{10}$$.

$$2814=10\cdot 281+4$$

$${2.814}_{10}={2.814}_{10}$$.

$$281=10\cdot 28+1$$

$${2.814}_{10}={2.814}_{10}$$.

$$28=10\cdot 2+8$$

$${2.814}_{10}={2.814}_{10}$$.

$$2=10\cdot 0+2$$

$${2.814}_{10}={2.814}_{10}$$.

$$2814$$

$${2.814}_{10}={2.814}_{10}$$.

$${\left(2814\right)}_{10}$$

$$2,{814}_{10}=2,{814}_{10}$$.